f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)(1)求最小正周期(2)若x∈[π/12,π/2],求f(x)的取值范围

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 03:01:08
f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)(1)求最小正周期(2)若x∈[π/12,π/2],求f(x)的取值范围

f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)(1)求最小正周期(2)若x∈[π/12,π/2],求f(x)的取值范围
f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)
(1)求最小正周期
(2)若x∈[π/12,π/2],求f(x)的取值范围

f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)(1)求最小正周期(2)若x∈[π/12,π/2],求f(x)的取值范围
f(x)=(1+cotx)sin²x-2sin(x+π/4)sin(x-π/4)
=sin²x+cotxsin²x+cos2x-cos(π/2)
=sin²x+sinxcosx+cos2x
=1/2*(2sin²x-1+2sinxcosx+1)+cos2x
=1/2*(sin2x-cos2x)+cos2x
=1/2*(sin2x+cos2x)
=√2/2*sin(2x+π/4)
T=2π/2=π
x∈[π/12,π/2]
2x∈[π/6,π]
2x+π/4∈[5π/12,5π/4]
sin(2x+π/4)∈[√2/2,1]
√2/2*sin(2x+π/4)∈[1/2,√2/2]
∴f(x)∈[1/2,√2/2]

f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, f(tanx)=sin(π/6-x)求:f(cotx)f(tanx)=sin(π/6-x) 求:f(cotx) f(x)=sin^3x(1+cotx)+cos^3x(1+tanx)+2的递增区间 高数补考…设F(X)=SIN^2×X-COS2X+COTX/2-LN2,求F'(X) 已知函数f(x)=(1+cotx)sin²x-2sin已知函数f(1+cotx)sinx^2-2sin(x+π/4)sin(x-π/4) 1、若tana=2,求f(a)2、若x∈[π/12,π/2],求f(x)的取值范围 f(x)=(1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)(1)求最小正周期(2)若x∈[π/12,π/2],求f(x)的取值范围 证 (sin^2x+sinx cosx -cotx)/(sin^2x-sinx cosx+cotx)=(1-cot^3 x)/(cot^3 x +1) 1.f(tanx)=sin(pai/6),f(cotx)=___ 2.f(x)=|cos(2x+pai/4)|+1递增区间为_____3.f(x)=2sin(2x+α+pai/6) 若0 已知函数f(x)=(1+cotx)sin^2(x)-2sin(x+∏/4)sin(x-∏/4),若tana=2,求f(a) ∫√(cotx+1)/(sin^2x)dx的不定积分 sin^2x/(1+cotx)+cos^2x/(1+tanx)=1-sinxcosx 证明:sin^2x(1+cotx)+cos^2x(1+tanx)=1-sinxcosx 已知函数f(1+cotx)sinx^2-2sin(x+π/4)sin(x-π/4)1、若tana=2,求f(a)2、若x∈[π/12,π/2],求f(x)的取值范围 已知函数f(1+cotx)sinx^2-2sin(x+π/4)sin(x-π/4)【急】1】若tana=2,求f(a)2】若x∈[π/12,π/2],求f(x)的取值范围 积分题 若∫f(x)dx=F(x)+C,则∫f(cotx)/sin²x dx=?-F(cotx)+C 一道简单不定积分题不定积分f(x)+c,则不定积分f(cotx)/sin^2xdx=? 已知f(x)=(sin2x-cos2x+1)/(1+cotx)(1)化简此函数解析式 (2)如果sin(x+π/4)=3/5,且π/4 已知函数f(x)=(1+cotx)sin^2x+msin(x+π/4)sin(x-π/4).当tanα=2时,f(α)=3/5,求m的值.