in 3.2 liters of an aqueous solution which was 0.0066 M with respect to CaCl2 and 0.5 M with regard to NaCl.每3.2升水溶解0.0066 M 氯化钙和0.5 M 氯化钠,其中的M 是什么单位,换成克是多少

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in 3.2 liters of an aqueous solution which was 0.0066 M with respect to CaCl2 and 0.5 M with regard to NaCl.每3.2升水溶解0.0066 M 氯化钙和0.5 M 氯化钠,其中的M 是什么单位,换成克是多少
in 3.2 liters of an aqueous solution which was 0.0066 M with respect to CaCl2 and 0.5 M with regard to NaCl.
每3.2升水溶解0.0066 M 氯化钙和0.5 M 氯化钠,其中的M 是什么单位,换成克是多少

in 3.2 liters of an aqueous solution which was 0.0066 M with respect to CaCl2 and 0.5 M with regard to NaCl.每3.2升水溶解0.0066 M 氯化钙和0.5 M 氯化钠,其中的M 是什么单位,换成克是多少
在3.2升水溶液中溶有0.0066 M 的氯化钙和0.5 M 的氯化钠.
其中的M 是物质的量浓度,也叫摩尔浓度,单位是mol/L;
CaCl2的质量= 0.0066 *3.2*111 =2.344克;
NaCl的质量= 0.5 *3.2*58.5 = 93.6克;
111是CaCl2的摩尔质量,58.5是NaCl的摩尔质量.

mol.乘以物质的量就可以了。

M
是摩尔（mol）物质的量的单位
0.0066 M 氯化钙
质量是：111g/mol×0.0066mol=0.7326g
0.5 M 氯化钠
质量是：58.5g/mol×0.5mol=29.25g

M指的是物质的量-摩尔，
物质的量是表示物质所含微粒数 1摩尔等于6.02×10^23个微粒
不同的物质摩尔每克的量不同，你得查元素周期表，一种物质每摩含多少克跟他的原子序数是相通的
0.0066 M 氯化钙
质量是：111g/mol×0.0066mol=0.7326g
0.5 M 氯化钠
质量是：58.5g/mol×0.5mol=29.2...

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摩尔...
是数量单位...1摩尔等于6.02×10^23（个微粒-）

你真舍得分，这个问题给100分，这根本不叫问题啊

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