已知sinxcosy=1/2 ,则cosxsiny的取值范围是?

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已知sinxcosy=1/2 ,则cosxsiny的取值范围是?

已知sinxcosy=1/2 ,则cosxsiny的取值范围是?
已知sinxcosy=1/2 ,则cosxsiny的取值范围是?

已知sinxcosy=1/2 ,则cosxsiny的取值范围是?
sinxcosy+cosxsiny=sin(x+y0
-1

sinxcosy+cosxsiny=sin(x+y0
-1<=sin(x+y)<=1
-1<=1/2+cosxsiny<=1
-3/2<=cosxsiny<=1/2
cosxsiny-sinxcosx=sin(y-x)
-1<=sin(y-x)<=1
-1<=cosxsiny-1/2<=1
-1/2<=cosxsiny<=3/2
-1/2<=cosxsiny<=1/2 cosxsiny-1/2<=1
-1/2<=cosxsiny<=3/2