mathematica数据拟合如何用mathematica得到非线性回归方程?data={{14.80,310},{18.74,700},{22.86,1160},{26.26,1800},{29.50,2680},{31.15,3200}}y=9616.5256/(1+256.32477Exp[-0.15570869])

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mathematica数据拟合如何用mathematica得到非线性回归方程?data={{14.80,310},{18.74,700},{22.86,1160},{26.26,1800},{29.50,2680},{31.15,3200}}y=9616.5256/(1+256.32477Exp[-0.15570869])

mathematica数据拟合如何用mathematica得到非线性回归方程?data={{14.80,310},{18.74,700},{22.86,1160},{26.26,1800},{29.50,2680},{31.15,3200}}y=9616.5256/(1+256.32477Exp[-0.15570869])
mathematica数据拟合
如何用mathematica得到非线性回归方程?
data={{14.80,310},{18.74,700},{22.86,1160},{26.26,1800},{29.50,2680},{31.15,3200}}
y=9616.5256/(1+256.32477Exp[-0.15570869])

mathematica数据拟合如何用mathematica得到非线性回归方程?data={{14.80,310},{18.74,700},{22.86,1160},{26.26,1800},{29.50,2680},{31.15,3200}}y=9616.5256/(1+256.32477Exp[-0.15570869])
data = {{14.80,310},{18.74,700},{22.86,1160},{26.26,1800},{29.50,2680},{31.15,3200}};
FindFit[data,a /(1 + b Exp[x]),{a,b},x]
把FindFit里的表达式改成你想要拟合的式子就可以了