0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环

来源：学生作业帮助网编辑：作业帮时间：2024/05/09 16:50:20

0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环
0.12+0.23+0.34+0.45+0.56
注意!都是循环的,例如0.12的12循环,0.23的23循环

0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环
0.12+0.23+0.34+0.45+0.56
=12/99+23/99+34/99+45/99+56/99
=170/99
=1.717171……
（答案绝对正确!这是涉及到怎样把循环小数化成分数的知识.）

=(0.1+0.2+0.3+0.4+0.5)+(0.02+0.03+0.04+0.05+0.06)
=1.5+0.2
=1.7

12/99+23/99+34/99+45/99+56/99=170/99

等于0.17的17循环(*^__^*)
表问为什么，计算器嗯出来的

(0.12+0.89)*8/2=1.01*4=4.04 等差数列原式=(0.1+0.8)0.12+0.89=1.01 0.23+0.78=1.01 0.34+0.67=1.01 0.45+0.

(0.12+0.23+0.34)×(0.23+0.34+0.45)-(0.12+0.23+0.34+0.45)×(0.23+0.34) （0.12+0.23+0.34）*（0.23+0.34+0.45）-（0.12+0.23+0.34+0.45）*（032+034）简便计算 0.12+0.23+0.34+0.45+0.56+0.67+0.78+0.89=? (1+0.23+0.34)*(0.23+0.34+0.45)-(1+0.23+0.34+0.45)*(0.23+0.34)简便运算（1+0.23+0.34）×（0.23+0.34+0.45）-（1+0.23+0.34+0.45）×（0.23+0.34） 0.12+0.23+0.34+0.45+0.56注意!都是循环的,例如0.12的12循环,0.23的23循环求解(1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)=? 简便运算 (1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23) (1+0.12+0.23)*(0.12+0.23+0.34)-(1+0.12+0.23+0.34)*(0.12+0.23)= （1+0.12+0.23）×（0.12+0.23+0.34）- （1+0.12+0.23+0.34）×（0.12+0.23）. (1+0.12+0.23)X(0.12+0.23+0.34)-(1+0.12+0.23+0.34)X(0.12+0.23)=? (1+0.12+0.23)乘(0.12+0.23+0.34)_(1+0.12+0.23+0.34)乘(0.12+0.23) 0.12+0.23+0.34+0.45+0.56+0.67+0.78注意是循环小数,循环节在第二位 0.12+0.23+0.34+0.45+0.56答案是几注：都是循环小数,第二位开始 0.12+0.23+0.34+0.45+0.56+0.67+0.78注意是循环小数,循环节在第二位《2》简便运算（1+0.12+0.23）X(0.12+0.23+0.34) - (1+0.12+0.34)X(0.12+0.23) （0.12＋0.23＋0.34）*（0.23＋0.34＋0.45）－（0.12＋0.23＋0.34＋0.45）这是题目,看我打字辛苦的份上帮帮我 (1+0.12+0.23)x(0.12+0.23+0.34)-(1+0.12+0.23+0.34)x(0.12+0.23)等于几?用简便方法计算!