化简:1/[cosa根号(1+sin^2a/cos^2a)]+2/[根号(1/sin^2a-1)tana]已知0

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 07:53:19
化简:1/[cosa根号(1+sin^2a/cos^2a)]+2/[根号(1/sin^2a-1)tana]已知0

化简:1/[cosa根号(1+sin^2a/cos^2a)]+2/[根号(1/sin^2a-1)tana]已知0
化简:1/[cosa根号(1+sin^2a/cos^2a)]+2/[根号(1/sin^2a-1)tana]
已知0

化简:1/[cosa根号(1+sin^2a/cos^2a)]+2/[根号(1/sin^2a-1)tana]已知0
1+sin²a+/cos²a=(sin²a+cos²a)/cos²a=1/cos²a
所以1/[cosa根号(1+sin^2a/cos^2a)]
=1/(cosa*|1/cosa|)
1/sin²a-1=(1-sin²a)/(sin²a)=(cosa/sina)²=cot²a
所以2/[根号(1/sin^2a-1)tana]
=2/(|cota|*tana)
若00
则原式=1/1+2/1=3
若π/2