通分:1/(x-1)²,2/x²-1,3/(x-1)(x-2)
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通分:1/(x-1)²,2/x²-1,3/(x-1)(x-2)
通分:1/(x-1)²,2/x²-1,3/(x-1)(x-2)
通分:1/(x-1)²,2/x²-1,3/(x-1)(x-2)
先分母因式分解得1/﹙x-1﹚²
2/﹙x²-1﹚=2/[﹙x+1﹚﹙x-1﹚]
3/[﹙x-1﹚﹙x-2﹚] 公分母是:﹙x+1﹚﹙x-1﹚²﹙x-2﹚
∴1/﹙x-1﹚²=[﹙x+1﹚﹙x-2﹚]/[﹙x+1﹚﹙x-1﹚²﹙x-2]
2/﹙x²-1﹚=2/[﹙x+1﹚﹙x-1﹚]=2[﹙x-1﹚﹙x-2﹚/[﹙x+1﹚﹙x-1﹚²﹙x-2﹚]
3/[﹙x-1﹚﹙x-2﹚]=3[﹙x+1﹚﹙x-1﹚]/[﹙x+1﹚﹙x-1﹚²﹙x-2﹚]
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