y)(1/sqrt(pi)*exp(-x.^2)*1/sqrt(pi)*exp(-y.^2)).*(sqrt(x.^2+y.^2)

y)(1/sqrt(pi)*exp(-x.^2)*1/sqrt(pi)*exp(-y.^2)).*(sqrt(x.^2+y.^2) MATLAB:Error using ==> inlineeval fplot('[ (1/((sqrt(2*pi))*1))*(exp(-(x.^2)/(2*1^2))),(1/((sqrt(2*pi))*2))*（exp(-(x.^2)/(2*2^2))),(1/((sqrt(2*pi))*4))*（exp(-(x.^2)/(2*4^2))),(1/((sqrt(2*pi))*（220/100）))*（exp(-(x.^2)/(2*（220/100）^2))) ] 如何用matlab解非线性方程组,求写成程序,万分感激!E1=-1/2/(betainc(1-y/x,1.5,y+1)+(y/x).^y*exp(x-y)*sqrt(1-y/x)*exp(y-x)/x+(y/x).^y*exp(x-y)*sqrt(pi)/2/x>^1.5*erfc(sqrt(x-y)))*(2/z.^2+1/k.^2)*(2/3*y*((y-2)*0.5*betainc(1-y/x,0.5,y-1)-( maple函数解不等式我用指令r=maple('solve(exp(-pi*x/sqrt(1-x^2)) y=sqrt(3)/2.*exp(-4*t.)*sin(4*sqrt(3)*t.+pi/3);t=[-1:0.01:1],用matlab语言怎么编? 求解matlab一个公式问题function y = fun(x)y=-20*exp(-0.2*sqrt((x(1)^2+x(2)^2)/2))-exp((cos(2*pi*x(1))+cos(2*pi*x(2)))/2)+20+2.71289;用matlab,定义了一个fun的M文件,文件里只有一个自变量x那么下面式子中的x(1)和x(2)是什 Matlab中出错,x没有定义,怎么办啊?大神们function y = fun(x)y=-20*exp(-0.2*sqrt((x(1)^2+x(2)^2)/2))-exp((cos(2*pi*x(1))+cos(2*pi*x(2)))/2)+20+2.71289; 问一个Matlab小问题两个m文件function [Q]=Q(x);syms u;Q=(1/sqrt(2*pi))*int(exp(-u^2/2),x,inf);x=-6:0.1:20;y=Q(x);为什么有错误? 关于有MATLAB求复杂的目标函数的最优解的问题?i=400;x(i)=i;syms Q Y;s1=int('1/(sqrt(2*pi)*(1-0.85)*Q/3)*exp(-(Y-Q)^2/(2*(1-0.85)*Q/3))',Y,0.85*Q,400)s2=int('1/(sqrt(2*pi)*(1-0.85)*Q/3)*exp(-(Y-Q)^2/(2*(1-0.85)*Q/3))',Y,400,x(i))s3=int( 大一的数学实验题,用matlab软件作图y=1/(sqrt(2*pi)*1715/600)*exp(-(x-u)^2/(2*((1715/600)^2)))u分别为0,-1,1 (在同一坐标系上作图） matlab绘制隐函数图象char a b f;syms x y f=exp((1/(5*sqrt(2*pi)))*exp(-(y-100)^2/50))；ezplot('int(int(f,y,0,969600*b-(20*a+20)*(2000-x)),x,500,2000)=500') matlab中的一道作图,我的代码是这样的：>> x=-2:0.1:2;y1=1/(sqrt(2*pi)*213/600)*exp(-x.^2/(2*(213/600)^2));y2=1/sqrt(2*pi)*213/600*exp(-(x+1).^2/(2*(213/600)^2));y3=1/sqrt(2*pi)*213/600*exp(-(x-1).^2/(2*(213/600)^2));plot(x,y1,x,y2,x,y3) MATLAB中dsolve解出的t是什么含义?我使用了dsolve（’Dy = sin(pi*x*y)‘）；然后结果中：atan(2/(1+exp(2*t*pi*x+2*C1*pi*x))*exp(t*pi*x+C1*pi*x),-(exp(2*t*pi*x+2*C1*pi*x)-1)/(1+exp(2*t*pi*x+2*C1*pi*x)))/x/pi有t和c1两个量,c1想 在MATLAB中这个式子f=(x-90)(1/(sqrt(2*pi)*0.3))*exp^(-((x-L)^2/(2*0.18)));哪里错误 怎么用matlab编程求(1/sqrt(2*pi))*exp(-t^2/2)在-inf到x上的积分呐? matlab rotate程序求大神修改t=0:pi/1000:3.5*pi;k=fix(2*t/pi)+1;x=0.5*sqrt(2)*cos(0.5*k*pi+0.25*pi)+k.*cos(t);y=0.5*sqrt(2)*sin(0.5*k*pi+0.25*pi)+k.*sin(t);h=plot(x,y,'r');m=pi:pi/20:4.5*pi;n=fix(2*m/pi)-1;x0=2*cos(1.25*pi);y0=2*sin(1.25*pi);x2= 用matlab求二重积分[1+cos(6*pi*x+8*pi*y)]*exp(-j*2*pi*(3*x+4*y)),试了好多次貌似都有错syms x y>> double (int(int(1+cos(6*pi*x+8*pi*y)*exp(-j*2*pi*(3*x+4*y)),-inf,inf),-inf,inf))Warning:Could not attach the property of being closeto the MATLAB surf 图k=1;q=50;u=2;x=1:0.1:10;y=1:0.1:10;d=sqrt(x^2+y^2);z=q/(4*pi*k*d)*(1/d)*exp(-u/(2*k)*(d-x)); 请问怎样做一个surf（x,y,z）图啊.