√cos²600º= A.+_√3/2 B.√3/2 C.-√3/2 D.1/2

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√cos²600º= A.+_√3/2 B.√3/2 C.-√3/2 D.1/2

√cos²600º= A.+_√3/2 B.√3/2 C.-√3/2 D.1/2
√cos²600º= A.+_√3/2 B.√3/2 C.-√3/2 D.1/2

√cos²600º= A.+_√3/2 B.√3/2 C.-√3/2 D.1/2
解由√cos²600º
=/cos600º/
=/cos(720°-120°)/
=/cos(-120°)/
=/cos120°/
=/-cos60°/
=/-1/2/
=1/2
故选D