4（2p+3q）²-（3p-q）²怎么算

4（2p+3q）²-（3p-q）²怎么算
4（2p+3q）²-（3p-q）²怎么算

4（2p+3q）²-（3p-q）²怎么算
方法一：
4(2p+3q)²-(3p-q)²
=[2(2p+3q)]²-(3p-q)²
=[2(2p+3q)+(3p-q)][2(2p+3q)-(3p-q)]
=(7p+5q)(p+7q)
方法二：
4(2p+3q)²-(3p-q)²
=4(4p²+12pq+9q²)-(9p²-6pq+q²)
=16p²+48pq+36q²-9p²+6pq-q²
=7p²+54pq+35q²
=(7p+5q)(p+7q)
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4(2p+3q+3p-q)(2p+3q-3p+q)
=4(5p+2q)(-p+4q)

4（2p+3q）²-（3p-q）²
=[2(2p+3q)+3p-q]*[2(2p+3q)-(3p-q)]
=(7p+5q)(p+7q)

4(2p+3q)²-(3p-q)²
=[2(2p+3q)]²-(3p-q)²
=[2(2p+3q)+(3p-q)][2(2p+3q)-(3p-q)]
=(7p+5q)(p+7q)

先因式分解，再合并向
原式=4(4p²+12pq+9q²)-(9p²-6pq+q²)
=7p²+54q²+35q²
=（7p+5q）（p+7q）