验证哥德巴赫猜想:一个不小于6 的偶数可以表示为两个素数之和,如6=3+3,8=3+5,10=3+7……要求是6~100之间我编的程序如下对了我们还没有学到函数哟·····#include#includevoid main(){ int i,j,k,a,b,leap=1

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验证哥德巴赫猜想:一个不小于6 的偶数可以表示为两个素数之和,如6=3+3,8=3+5,10=3+7……要求是6~100之间我编的程序如下对了我们还没有学到函数哟·····#include#includevoid main(){ int i,j,k,a,b,leap=1
验证哥德巴赫猜想:一个不小于6 的偶数可以表示为两个素数之和,如6=3+3,8=3+5,10=3+7……要求是6~100之间
我编的程序如下对了我们还没有学到函数哟·····
#include
#include
void main()
{ int i,j,k,a,b,leap=1,sum=0;
for(a=6;a

验证哥德巴赫猜想:一个不小于6 的偶数可以表示为两个素数之和,如6=3+3,8=3+5,10=3+7……要求是6~100之间我编的程序如下对了我们还没有学到函数哟·····#include#includevoid main(){ int i,j,k,a,b,leap=1
#include "stdio.h"
bool prime(int n) {
for(int i = 2; i < n; i++)
if(n%i==0) return false;
return true;
}
int main () {
int m, n, count = 0;
scanf("%d%d", &m, &n);
for(int i = m; i <= n; i++) {
for(int j = 2; j <= i/2; j++) {
if (prime(j)&&(i-j)) {
printf("%d=%d+%d ", i, j, i-j);
count++;
if(count%5 == 0) printf("\n");
}
}
}
return 0;
}
#include "stdio.h"
#include "math.h"
int main(void)
{
int count, i, j, k, m, n, number;
scanf("%d%d", &m, &n);
if(m % 2 != 0) m = m + 1;
if(m >= 6){
count = 0;
for(i = m; i <= n; i+=2) {
for(j = 2; j <= i/2; j++) {
number= 1;
for(k=2;k if(j%k==0) number = 0;
for(k=2;k if((i-j)%k==0) number = 0;
if(number == 1) {
printf("%d=%d+%d ", i, j, i-j);
count++;
if(count%5 == 0) printf("\n");
break;
}
}
}
}
}
居然是填空题,疯了……

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表格（三）：偶数表为两个奇质数之和的表法的数量——公式计算数与实际表法数之比
Gc（N）≡ Ctwin × K × 4 / N × Sha（N/2）×（ Sha（N）－ Sha（N/2））; K ≡ 4.7593318809
Ctwin ≡ 0.6601618158468; Sha（N）≡ 2 /（1＋√（1－4/Ln（N）））× N/ Ln（N）
HNGp（N）Sha（N）Sha（N/2）Gc（N）Gc / Gp
1646969323043755729300333274.349155171875.98443755922.8541.00000443038
21293938646082116003581899754.297300333274.34982134780.5051.00022867047
319409079690118808995857185414.630442158083.119118824420.8391.00012983730
4258787729201544612911128545184.65581899754.297154477985.9621.00010808508
5323484661501893600431397058598.85720132249.812189389705.7791.00015664751
6388181593802237100821663346502.21857185414.630223726819.0721.00007481590
7452878526102575557311927811728.25993273148.864257596871.3481.00015973377
8517575458402910421932190736390.321128545184.65291074634.3351.00011146609
9582272390703241858642452328817.441263112051.68324214987.3171.00008983524
10646969323003570228552712748986.191397058598.85357059850.2671.00010362156
11711666255303895841462972123493.731530451952.34389642242.5691.00014912457
12776363187604219404123230554943.071663346502.21421988814.4771.00011471401
13841060119904540680263488128121.821795787184.42454121506.3721.00011778053
14905757052204860015773744914234.091927811728.25486058680.7371.00011749702
15970453984505177562454000973895.212059452246.24517815920.3141.00011525754
161035150916805493533184256359309.742190736390.32549406606.6821.00009700256
171099847849105807574294511115892.732321688212.33580842349.6571.00014622397
181164544781406120641324765283501.312452328817.44612133312.5331.00011302824
191229241713706431948645018897386.542582676869.27643288462.8181.00014552171
201293938646006742266935271988940.712712748986.19674315768.5771.00013211517
211358635578307051612065524586291.892842560056.76705222354.3081.00008671536
221423332510607359302365776714782.942972123493.73736014626.2321.00011467151
231488029442907666095696028397361.603101451440.86766698374.1151.00011584138
241552726375207972045696279654901.283230554943.07797278854.8521.00009318292
251617423307508276803866530506467.353359444087.54827760861.6981.00009723040
261682120239808580296486780969539.913488128121.82858148782.1011.00013884613
271746817172108883569097031060201.583616615553.38888446646.3581.00010101498
281811514104409185385907280793296.933744914234.09918658168.8651.00013018382
291876211036709486984867530182568.643873031432.37948786783.2821.00009307201
301940907969009787165637779240774.534000973895.21978835672.7191.00012169991
3120056049013010434683868027979788.674128747901.751008807795.760.96678328668
Sha YinYue, Room 105, 9, TaoYuanXinCun, HengXi Town, NingBo City , Z. J. 315131 , CHINA

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验证哥德巴赫猜想:一个不小于6 的偶数可以表示为两个素数之和,如6=3+3,8=3+5,10=3+7……要求是6~100之间我编的程序如下 对了 我们还没有学到函数哟·····#include#includevoid main(){ int i,j,k,a,b,leap=1

验证哥德巴赫猜想:一个不小于6 的偶数可以表示为两个素数之和,如6=3+3,8=3+5,10=3+7……要求是6~100之间我编的程序如下对了我们还没有学到函数哟·····#include#includevoid main(){ int i,j,k,a,b,leap=1