(2x+1)^2+3(x-2)^2=7(x+3)(x-3)

(2x+1)^2+3(x-2)^2=7(x+3)(x-3)
(2x+1)^2+3(x-2)^2=7(x+3)(x-3)

(2x+1)^2+3(x-2)^2=7(x+3)(x-3)
首先把式子展开如下:
4x^2+4x+1+3x^2-12x+12=7x^2-63
化简得:
-8x=-76

x=19/2

(2x+1)^2+3(x-2)^2=7(x+3)(x-3)
【解】4x^2+4x+1+3x^2-12x+12=7x^2-63
-8x=-76
x=-19/2

【解】4x^2+4x+1+3x^2-12x+12=7x^2-63
-8x=-76
x=19/2=9.5