若sin(π/2+θ)=3/5,则cos2θ=?

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若sin(π/2+θ)=3/5,则cos2θ=?

若sin(π/2+θ)=3/5,则cos2θ=?
若sin(π/2+θ)=3/5,则cos2θ=?

若sin(π/2+θ)=3/5,则cos2θ=?
sin(π/2+θ)=cosa=3/5
cosa=3/5
(cosa)^2=9/25
(sina)^2=16/25
cos2a=(cosa)^2-(sina)^2=-7/25

sin(π/2+θ)=3/5,
cosθ=3/5
cos2θ=2cos^2θ-1
=18/25-1=-7/25

利用诱导公式
sin(π/2+θ)=cosθ=3/5
cos2θ=2cosθ的平方-1=-7/25

sin(π/2+θ)=sin(π/2)cosθ+cos(π/2)sinθ=cosθ=3/5
cos2θ=2(cosθ)^2-1=2*(3/5)^2-1=18/25-1=-7/25cosβ=-1/3,sin(x+β)=7/9,且x∈(0,π/2),β∈(π/2,π),则cosx=?β∈(π/2,π),0sinx>0, 1...

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sin(π/2+θ)=sin(π/2)cosθ+cos(π/2)sinθ=cosθ=3/5
cos2θ=2(cosθ)^2-1=2*(3/5)^2-1=18/25-1=-7/25

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