解不等式:log∨3 (3+2x-x²)＞log∨3 (3x+1)

解不等式:log∨3 (3+2x-x²)＞log∨3 (3x+1)
解不等式:log∨3 (3+2x-x²)＞log∨3 (3x+1)

解不等式:log∨3 (3+2x-x²)＞log∨3 (3x+1)
由于以3为底的对数函数是增函数,
从而原不等式等价为
3+2x-x²>3x+1>0
即 x²+x-2-1/3
-2