函数f[x]=sin[2x+φ],φ属于[-π/2 π/2]的图像关于直线x=π/12对称则φ等于

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 08:32:24
函数f[x]=sin[2x+φ],φ属于[-π/2 π/2]的图像关于直线x=π/12对称则φ等于

函数f[x]=sin[2x+φ],φ属于[-π/2 π/2]的图像关于直线x=π/12对称则φ等于
函数f[x]=sin[2x+φ],φ属于[-π/2 π/2]的图像关于直线x=π/12对称则φ等于

函数f[x]=sin[2x+φ],φ属于[-π/2 π/2]的图像关于直线x=π/12对称则φ等于
f(π/12)=+ -1
sin((π/6)+φ)=+ -1
而:-π/3

已知函数f(x)=2sin(wx+φ),x属于R,w>0,-π 函数f(x)=sin(2x+φ)((|φ| 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(0 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+φ)(0 已知函数f(x)=sin(2x+φ) (0 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数f（x）=2sin（2x-pai／4）,若f（x+φ）为奇函数,φ属于[0,2pai）,求φ