作业帮3道计算,1)(x^2)·(x^3y^2)÷x^12 2)(2a^2y)^3÷(-1/2a^5y^2)(-2ay) 3)(m+n)(m-n)[mn-(m+n)^2][(m-n)^2+mn)]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/04 12:11:16
![3道计算,1)(x^2)·(x^3y^2)÷x^12 2)(2a^2y)^3÷(-1/2a^5y^2)(-2ay) 3)(m+n)(m-n)[mn-(m+n)^2][(m-n)^2+mn)]](/uploads/image/z/14495501-29-1.jpg?t=3%E9%81%93%E8%AE%A1%E7%AE%97%2C1%29%28x%5E2%29%C2%B7%28x%5E3y%5E2%29%C3%B7x%5E12+2%29%282a%5E2y%29%5E3%C3%B7%28-1%2F2a%5E5y%5E2%29%28-2ay%29+3%29%28m%2Bn%29%28m-n%29%5Bmn-%28m%2Bn%29%5E2%5D%5B%28m-n%29%5E2%2Bmn%29%5D)
3道计算,1)(x^2)·(x^3y^2)÷x^12 2)(2a^2y)^3÷(-1/2a^5y^2)(-2ay) 3)(m+n)(m-n)[mn-(m+n)^2][(m-n)^2+mn)]
3道计算,
1)(x^2)·(x^3y^2)÷x^12
2)(2a^2y)^3÷(-1/2a^5y^2)(-2ay)
3)(m+n)(m-n)[mn-(m+n)^2][(m-n)^2+mn)]
3道计算,1)(x^2)·(x^3y^2)÷x^12 2)(2a^2y)^3÷(-1/2a^5y^2)(-2ay) 3)(m+n)(m-n)[mn-(m+n)^2][(m-n)^2+mn)]
1)(x^2)·(x^3y^2)÷x^12 =x^5y^2÷x^12=x^-7y^2
2)(2a^2y)^3÷(-1/2a^5y^2)(-2ay)
=8a^6y^3÷(a^6y^3)
=8
3)(m+n)(m-n)[mn-(m-n)^2][(m-n)^2+mn)]
=(m²-n²
这个题目是错的
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