f(1/sinxcosx)dx

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f(1/sinxcosx)dx
∫dx/(1+sinxcosx)^2

∫dx/(1+sinxcosx)^2∫dx/(1+sinxcosx)^2∫dx/(1+sinxcosx)^2令v=tanx,dx=dv/(1+v^2),sinx=v/√(1+v^2),cosv=1/√

∫sinxcosx/(1+sin^4x)dx

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求不定积分sinxcosx/1+sinx^4dx求不定积分sinxcosx/1+sinx^4dx求不定积分sinxcosx/1+sinx^4dx∫sinxcosx/(1+sin^4x)dx=∫sinx

∫sinxcosx/[1+(sinx)^4)]dx

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∫(1/sinxcosx)dx 求定积分

∫(1/sinxcosx)dx求定积分∫(1/sinxcosx)dx求定积分∫(1/sinxcosx)dx求定积分∫(1/sinxcosx)dx=∫1/sinx*d(sinx)=1/2(sinx)^2

∫cos2x/(1+sinxcosx) dx 求详解.

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∫(sinxcosx)/(1+sinx^4)dx求导?

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积分 sinxcosx/(1+sin^2x)^5 dx

积分sinxcosx/(1+sin^2x)^5dx积分sinxcosx/(1+sin^2x)^5dx 积分sinxcosx/(1+sin^2x)^5dx全部展开收起原式=1/2∫1/(1+s

求解∫(x+2sinxcosx)/(1+cos2x) dx

求解∫(x+2sinxcosx)/(1+cos2x)dx求解∫(x+2sinxcosx)/(1+cos2x)dx求解∫(x+2sinxcosx)/(1+cos2x)dx∫(x+2sinxcosx)/(

∫cosx^2/1+sinxcosx dx如何求解

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∫(COS2X)/(1十SinXCOSX)dX=

∫(COS2X)/(1十SinXCOSX)dX=∫(COS2X)/(1十SinXCOSX)dX=∫(COS2X)/(1十SinXCOSX)dX=∫(COS2X)/(1十SinXCOSX)dX=∫(1/

∫sinxcosx/(sinx+cosx)dx

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求不定积分∫dx/(sinxcosx)

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∫cos2x/(sinxcosx)^2dx

∫cos2x/(sinxcosx)^2dx∫cos2x/(sinxcosx)^2dx∫cos2x/(sinxcosx)^2dx∫cos2x/(sinxcosx)^2dx=∫√2cos2x/(2sinx

化简f(x)=cos2x+sinxcosx+1

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1.∫(sinxcosx)/(1+sin^2x)dx2.设f'(sinx)=cos^2x 则f(x)=3.已知 f'(cosx)=sinx 则f(cosx)=4.∫dx/(e^x-1)^1/2=.....第三题的答案 最后给的是 1/2 (sinxcosx-x)+c

1.∫(sinxcosx)/(1+sin^2x)dx2.设f''(sinx)=cos^2x则f(x)=3.已知f''(cosx)=sinx则f(cosx)=4.∫dx/(e^x-1)^1/2=.....第

已知f(tanx)=1/sinxcosx,求f(x)=

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计算不定积分1.∫(sinXcosx)/(1+sin^4 X)dx 2.∫dx/(X^2 (4-X^2)^1/2)

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计算不定积分1.∫(sinXcosx)/(1+sin^4 X)dx 2.∫dx/(X^2 (4-X^2)^0.5

计算不定积分1.∫(sinXcosx)/(1+sin^4X)dx2.∫dx/(X^2(4-X^2)^0.5计算不定积分1.∫(sinXcosx)/(1+sin^4X)dx2.∫dx/(X^2(4-X^